Light of wavelength 6000 , mathring{A} is inc | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Wavelength $\lambda = 6000 \, \mathring{A} = 6000 	imes 10^{-10} \, m = 6 	imes 10^{-7} \, m$. Slit width $a = 0.3 \, mm = 0.3 	imes 10^

Vedclass · Accepted Answer

$2 	imes 10^{-3} \, rad$

Vedclass · Answer

(A) Given: Wavelength $\lambda = 6000 \, \mathring{A} = 6000 	imes 10^{-10} \, m = 6 	imes 10^{-7} \, m$. Slit width $a = 0.3 \, mm = 0.3 	imes 10^{-3} \, m = 3 	imes 10^{-4} \, m$. For the first minima in single slit diffraction,the condition is given by $a \sin 	heta = n \lambda$. For the first minima,$n = 1$. So,$a \sin 	heta = \lambda$. Since $	heta$ is very small,$\sin 	heta \approx 	heta$. Therefore,$	heta = \frac{\lambda}{a}$. Substituting the values: $	heta = \frac{6 	imes 10^{-7}}{3 	imes 10^{-4}} = 2 	imes 10^{-3} \, rad$.

Light of wavelength $6000 \, \mathring{A}$ is incident on a single slit of width $0.3 \, mm$. The angular position of the first minima will be

Similar Questions

The first minima due to a single slit diffraction is at $\theta = 30^o$ for a light of wavelength $5000 \, \mathring{A}$. The width of the slit is

Radio waves diffract around buildings,although light waves do not. The reason is that radio waves

Light of wavelength $5000 \, \mathring{A}$ is incident on a single slit such that the first minima is formed at a distance $5 \, mm$ from the centre. If the screen is placed $2 \, m$ away,then find the width of the slit in $mm$.

Explain diffraction by a single slit.

Vedclass Test Series

Exam Paper Generator

Online Exam Module